Optimal. Leaf size=127 \[ \frac{8 \tan ^9(c+d x)}{9 a^4 d}+\frac{16 \tan ^7(c+d x)}{7 a^4 d}+\frac{9 \tan ^5(c+d x)}{5 a^4 d}+\frac{\tan ^3(c+d x)}{3 a^4 d}-\frac{8 \sec ^9(c+d x)}{9 a^4 d}+\frac{12 \sec ^7(c+d x)}{7 a^4 d}-\frac{4 \sec ^5(c+d x)}{5 a^4 d} \]
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Rubi [A] time = 0.309682, antiderivative size = 127, normalized size of antiderivative = 1., number of steps used = 17, number of rules used = 5, integrand size = 21, \(\frac{\text{number of rules}}{\text{integrand size}}\) = 0.238, Rules used = {2711, 2607, 270, 2606, 14} \[ \frac{8 \tan ^9(c+d x)}{9 a^4 d}+\frac{16 \tan ^7(c+d x)}{7 a^4 d}+\frac{9 \tan ^5(c+d x)}{5 a^4 d}+\frac{\tan ^3(c+d x)}{3 a^4 d}-\frac{8 \sec ^9(c+d x)}{9 a^4 d}+\frac{12 \sec ^7(c+d x)}{7 a^4 d}-\frac{4 \sec ^5(c+d x)}{5 a^4 d} \]
Antiderivative was successfully verified.
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Rule 2711
Rule 2607
Rule 270
Rule 2606
Rule 14
Rubi steps
\begin{align*} \int \frac{\tan ^2(c+d x)}{(a+a \sin (c+d x))^4} \, dx &=\frac{\int \left (a^4 \sec ^8(c+d x) \tan ^2(c+d x)-4 a^4 \sec ^7(c+d x) \tan ^3(c+d x)+6 a^4 \sec ^6(c+d x) \tan ^4(c+d x)-4 a^4 \sec ^5(c+d x) \tan ^5(c+d x)+a^4 \sec ^4(c+d x) \tan ^6(c+d x)\right ) \, dx}{a^8}\\ &=\frac{\int \sec ^8(c+d x) \tan ^2(c+d x) \, dx}{a^4}+\frac{\int \sec ^4(c+d x) \tan ^6(c+d x) \, dx}{a^4}-\frac{4 \int \sec ^7(c+d x) \tan ^3(c+d x) \, dx}{a^4}-\frac{4 \int \sec ^5(c+d x) \tan ^5(c+d x) \, dx}{a^4}+\frac{6 \int \sec ^6(c+d x) \tan ^4(c+d x) \, dx}{a^4}\\ &=\frac{\operatorname{Subst}\left (\int x^6 \left (1+x^2\right ) \, dx,x,\tan (c+d x)\right )}{a^4 d}+\frac{\operatorname{Subst}\left (\int x^2 \left (1+x^2\right )^3 \, dx,x,\tan (c+d x)\right )}{a^4 d}-\frac{4 \operatorname{Subst}\left (\int x^6 \left (-1+x^2\right ) \, dx,x,\sec (c+d x)\right )}{a^4 d}-\frac{4 \operatorname{Subst}\left (\int x^4 \left (-1+x^2\right )^2 \, dx,x,\sec (c+d x)\right )}{a^4 d}+\frac{6 \operatorname{Subst}\left (\int x^4 \left (1+x^2\right )^2 \, dx,x,\tan (c+d x)\right )}{a^4 d}\\ &=\frac{\operatorname{Subst}\left (\int \left (x^6+x^8\right ) \, dx,x,\tan (c+d x)\right )}{a^4 d}+\frac{\operatorname{Subst}\left (\int \left (x^2+3 x^4+3 x^6+x^8\right ) \, dx,x,\tan (c+d x)\right )}{a^4 d}-\frac{4 \operatorname{Subst}\left (\int \left (x^4-2 x^6+x^8\right ) \, dx,x,\sec (c+d x)\right )}{a^4 d}-\frac{4 \operatorname{Subst}\left (\int \left (-x^6+x^8\right ) \, dx,x,\sec (c+d x)\right )}{a^4 d}+\frac{6 \operatorname{Subst}\left (\int \left (x^4+2 x^6+x^8\right ) \, dx,x,\tan (c+d x)\right )}{a^4 d}\\ &=-\frac{4 \sec ^5(c+d x)}{5 a^4 d}+\frac{12 \sec ^7(c+d x)}{7 a^4 d}-\frac{8 \sec ^9(c+d x)}{9 a^4 d}+\frac{\tan ^3(c+d x)}{3 a^4 d}+\frac{9 \tan ^5(c+d x)}{5 a^4 d}+\frac{16 \tan ^7(c+d x)}{7 a^4 d}+\frac{8 \tan ^9(c+d x)}{9 a^4 d}\\ \end{align*}
Mathematica [A] time = 0.415533, size = 124, normalized size = 0.98 \[ \frac{\sec (c+d x) (34944 \sin (c+d x)+1776 \sin (2 (c+d x))-9504 \sin (3 (c+d x))-296 \sin (4 (c+d x))+352 \sin (5 (c+d x))+1554 \cos (c+d x)-16896 \cos (2 (c+d x))-999 \cos (3 (c+d x))+2816 \cos (4 (c+d x))+37 \cos (5 (c+d x))+16128)}{80640 a^4 d (\sin (c+d x)+1)^4} \]
Antiderivative was successfully verified.
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Maple [A] time = 0.076, size = 158, normalized size = 1.2 \begin{align*} 8\,{\frac{1}{d{a}^{4}} \left ( -{\frac{1}{128\,\tan \left ( 1/2\,dx+c/2 \right ) -128}}-2/9\, \left ( \tan \left ( 1/2\,dx+c/2 \right ) +1 \right ) ^{-9}+ \left ( \tan \left ( 1/2\,dx+c/2 \right ) +1 \right ) ^{-8}-{\frac{29}{14\, \left ( \tan \left ( 1/2\,dx+c/2 \right ) +1 \right ) ^{7}}}+{\frac{31}{12\, \left ( \tan \left ( 1/2\,dx+c/2 \right ) +1 \right ) ^{6}}}-{\frac{83}{40\, \left ( \tan \left ( 1/2\,dx+c/2 \right ) +1 \right ) ^{5}}}+{\frac{17}{16\, \left ( \tan \left ( 1/2\,dx+c/2 \right ) +1 \right ) ^{4}}}-{\frac{29}{96\, \left ( \tan \left ( 1/2\,dx+c/2 \right ) +1 \right ) ^{3}}}+{\frac{1}{64\, \left ( \tan \left ( 1/2\,dx+c/2 \right ) +1 \right ) ^{2}}}+{\frac{1}{128\,\tan \left ( 1/2\,dx+c/2 \right ) +128}} \right ) } \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Maxima [B] time = 3.08174, size = 481, normalized size = 3.79 \begin{align*} \frac{8 \,{\left (\frac{16 \, \sin \left (d x + c\right )}{\cos \left (d x + c\right ) + 1} + \frac{54 \, \sin \left (d x + c\right )^{2}}{{\left (\cos \left (d x + c\right ) + 1\right )}^{2}} + \frac{201 \, \sin \left (d x + c\right )^{3}}{{\left (\cos \left (d x + c\right ) + 1\right )}^{3}} + \frac{294 \, \sin \left (d x + c\right )^{4}}{{\left (\cos \left (d x + c\right ) + 1\right )}^{4}} + \frac{378 \, \sin \left (d x + c\right )^{5}}{{\left (\cos \left (d x + c\right ) + 1\right )}^{5}} + \frac{210 \, \sin \left (d x + c\right )^{6}}{{\left (\cos \left (d x + c\right ) + 1\right )}^{6}} + \frac{105 \, \sin \left (d x + c\right )^{7}}{{\left (\cos \left (d x + c\right ) + 1\right )}^{7}} + 2\right )}}{315 \,{\left (a^{4} + \frac{8 \, a^{4} \sin \left (d x + c\right )}{\cos \left (d x + c\right ) + 1} + \frac{27 \, a^{4} \sin \left (d x + c\right )^{2}}{{\left (\cos \left (d x + c\right ) + 1\right )}^{2}} + \frac{48 \, a^{4} \sin \left (d x + c\right )^{3}}{{\left (\cos \left (d x + c\right ) + 1\right )}^{3}} + \frac{42 \, a^{4} \sin \left (d x + c\right )^{4}}{{\left (\cos \left (d x + c\right ) + 1\right )}^{4}} - \frac{42 \, a^{4} \sin \left (d x + c\right )^{6}}{{\left (\cos \left (d x + c\right ) + 1\right )}^{6}} - \frac{48 \, a^{4} \sin \left (d x + c\right )^{7}}{{\left (\cos \left (d x + c\right ) + 1\right )}^{7}} - \frac{27 \, a^{4} \sin \left (d x + c\right )^{8}}{{\left (\cos \left (d x + c\right ) + 1\right )}^{8}} - \frac{8 \, a^{4} \sin \left (d x + c\right )^{9}}{{\left (\cos \left (d x + c\right ) + 1\right )}^{9}} - \frac{a^{4} \sin \left (d x + c\right )^{10}}{{\left (\cos \left (d x + c\right ) + 1\right )}^{10}}\right )} d} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Fricas [A] time = 1.49638, size = 338, normalized size = 2.66 \begin{align*} \frac{88 \, \cos \left (d x + c\right )^{4} - 220 \, \cos \left (d x + c\right )^{2} +{\left (22 \, \cos \left (d x + c\right )^{4} - 165 \, \cos \left (d x + c\right )^{2} + 175\right )} \sin \left (d x + c\right ) + 140}{315 \,{\left (a^{4} d \cos \left (d x + c\right )^{5} - 8 \, a^{4} d \cos \left (d x + c\right )^{3} + 8 \, a^{4} d \cos \left (d x + c\right ) - 4 \,{\left (a^{4} d \cos \left (d x + c\right )^{3} - 2 \, a^{4} d \cos \left (d x + c\right )\right )} \sin \left (d x + c\right )\right )}} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Sympy [F] time = 0., size = 0, normalized size = 0. \begin{align*} \frac{\int \frac{\tan ^{2}{\left (c + d x \right )}}{\sin ^{4}{\left (c + d x \right )} + 4 \sin ^{3}{\left (c + d x \right )} + 6 \sin ^{2}{\left (c + d x \right )} + 4 \sin{\left (c + d x \right )} + 1}\, dx}{a^{4}} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Giac [A] time = 2.53876, size = 197, normalized size = 1.55 \begin{align*} -\frac{\frac{315}{a^{4}{\left (\tan \left (\frac{1}{2} \, d x + \frac{1}{2} \, c\right ) - 1\right )}} - \frac{315 \, \tan \left (\frac{1}{2} \, d x + \frac{1}{2} \, c\right )^{8} + 3150 \, \tan \left (\frac{1}{2} \, d x + \frac{1}{2} \, c\right )^{7} + 1050 \, \tan \left (\frac{1}{2} \, d x + \frac{1}{2} \, c\right )^{6} + 630 \, \tan \left (\frac{1}{2} \, d x + \frac{1}{2} \, c\right )^{5} - 8064 \, \tan \left (\frac{1}{2} \, d x + \frac{1}{2} \, c\right )^{4} - 6006 \, \tan \left (\frac{1}{2} \, d x + \frac{1}{2} \, c\right )^{3} - 5274 \, \tan \left (\frac{1}{2} \, d x + \frac{1}{2} \, c\right )^{2} - 846 \, \tan \left (\frac{1}{2} \, d x + \frac{1}{2} \, c\right ) - 59}{a^{4}{\left (\tan \left (\frac{1}{2} \, d x + \frac{1}{2} \, c\right ) + 1\right )}^{9}}}{5040 \, d} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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